document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=442900>Question 442900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A & B are traveling the the same direction on parallel tracks.  Train A at 80 MPH and Train B at 96 MPH. Train A passes a station at 4:25 p.m. If Train B passes the same station at 4:40 p.m., what time will Train B catch up to Train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305517 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Trains A & B are traveling the the same direction on parallel tracks.  Train A at 80 MPH and Train B at 96 MPH. Train A passes a station at 4:25 p.m. If Train B passes the same station at 4:40 p.m., what time will Train B catch up to Train A?<BR>\n" );
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document.write( "In 12 minutes (440 - 425), train A goes 16 miles (80 mph * 1/5 hour).  It's 16 miles ahead when train B passes the station at 440.<BR>\n" );
document.write( "Train B gains on train A at 16 mph (96 - 80).<BR>\n" );
document.write( "16 miles/16 mph = 1 hour<BR>\n" );
document.write( "4:40 + 1 = 5:40 PM<BR>\n" );
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