document.write( "Question 442911: a rectangle has a length of five inches longer than the width\"w\" if the perimeter is 38 inches, find the dimensions of the rectangle \n" ); document.write( "

Algebra.Com's Answer #305511 by swincher4391(1107) $\"\"$ $\"About$

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The perimeter formula is $\"P+=+2l+%2B+2w\"$ where P is the perimeter, l is the length and w is the width.\r
\n" ); document.write( "\n" ); document.write( "They say that the length is 5 inches longer than the width, then $\"w%2B5+=+l\"$ \r
\n" ); document.write( "\n" ); document.write( "We know $\"P+=+38\"$ \r
\n" ); document.write( "\n" ); document.write( "So, putting it all together:\r
\n" ); document.write( "\n" ); document.write( " $\"+38+=+2l+%2B2w+=+2%28w%2B5%29+%2B+2w\"$
\n" ); document.write( " $\"2w%2B10+%2B+2w+=+4w%2B10+=+38\"$
\n" ); document.write( " $\"4w+=+28\"$
\n" ); document.write( " $\"w+=+7\"$ \r
\n" ); document.write( "\n" ); document.write( "We know our width is 7.\r
\n" ); document.write( "\n" ); document.write( "Plug it back into w+5 =l.\r
\n" ); document.write( "\n" ); document.write( " $\"l+=+7%2B5+=+highlight%2812%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Our length is 12.\r
\n" ); document.write( "\n" ); document.write( "So our dimensions are 12 x 7.\r
\n" ); document.write( "\n" ); document.write( "Let's check this to make sure.\r
\n" ); document.write( "\n" ); document.write( "They say the perimeter is 38, then 12(2) + 7(2) better = 38.\r
\n" ); document.write( "\n" ); document.write( "24 + 14 = 38. Check.\r
\n" ); document.write( "\n" ); document.write( "Hope this helps!\r
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