document.write( "Question 46031: log9 (x-3) + log9 (x-3)= 1 \n" ); document.write( "
Algebra.Com's Answer #30551 by fractalier(6550)\"\" \"About 
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Okay from
\n" ); document.write( "log9 (x-3) + log9 (x-3)= 1
\n" ); document.write( "we combine to get
\n" ); document.write( "2*log9 (x-3) = 1
\n" ); document.write( "log9 [(x-3)^2] = 1
\n" ); document.write( "now exponentiate \"nine to the...\" and get
\n" ); document.write( "[(x-3)^2] = 9
\n" ); document.write( "x - 3 = ±3
\n" ); document.write( "and x = 6 or x = 0
\n" ); document.write( "but x cannot be zero, so
\n" ); document.write( "x = 6 \n" ); document.write( "
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