document.write( "Question 442804: how many ounces of a 30% solution must be added to 50 ounces of a 12% saline solution to make a 20% saline solution? Show work please. \n" ); document.write( "
Algebra.Com's Answer #305468 by kittycat1613(12)![]() ![]() ![]() You can put this solution on YOUR website! Let x= # of ounces of 30% solution \n" ); document.write( " x+50= # of ounces of 20% saline solution \n" ); document.write( ".3(x)+.12(50)=.2(x+50) \n" ); document.write( ".3(x)+6=.2x+10 \n" ); document.write( "-.2x -6 -.2x -6 \n" ); document.write( "[.1x=4]*10 \n" ); document.write( "1x=40 \n" ); document.write( "x=40\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "40(.3)+50(.12)=90(.2) \n" ); document.write( "12+6=18 \n" ); document.write( "18=18 \n" ); document.write( "Correct\r \n" ); document.write( "\n" ); document.write( "Answer: 40 ounces of a 30% solution must be added \n" ); document.write( " \n" ); document.write( " |