document.write( "Question 442804: how many ounces of a 30% solution must be added to 50 ounces of a 12% saline solution to make a 20% saline solution? Show work please. \n" ); document.write( "
Algebra.Com's Answer #305468 by kittycat1613(12)\"\" \"About 
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Let x= # of ounces of 30% solution
\n" ); document.write( " x+50= # of ounces of 20% saline solution
\n" ); document.write( ".3(x)+.12(50)=.2(x+50)
\n" ); document.write( ".3(x)+6=.2x+10
\n" ); document.write( "-.2x -6 -.2x -6
\n" ); document.write( "[.1x=4]*10
\n" ); document.write( "1x=40
\n" ); document.write( "x=40\r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "40(.3)+50(.12)=90(.2)
\n" ); document.write( "12+6=18
\n" ); document.write( "18=18
\n" ); document.write( "Correct\r
\n" ); document.write( "\n" ); document.write( "Answer: 40 ounces of a 30% solution must be added
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