document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=442617>Question 442617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello,\r<BR>\n" );
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document.write( "I have a problem that states the following that I'm having a hard time getting passed:\r<BR>\n" );
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document.write( "\"Use the Pythagorean Theorem to find the lengths of the sides of the triangle.\"\r<BR>\n" );
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document.write( "On the picture it shows the point of the triangle pointing to the left. The short base (or possibly the height) on the right shows the numbers (2x-3). \r<BR>\n" );
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document.write( "The bottom long base part of the triangle shows (15)\r<BR>\n" );
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document.write( "The top slanted side shows (2x)\r<BR>\n" );
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document.write( "Then it asks for the lengths of the missing sides are:__________.\r<BR>\n" );
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document.write( "Any help on this problem would be greatly appreciated.   :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305428 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305428\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since you mention Pythagoras, it's a right triangle.<BR>\n" );
document.write( "2x is the hypotentuse, the longest side.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282x%29%5E2+=+15%5E2+%2B+%282x-3%29%5E2 ALIGN=MIDDLE  ALT=\"%282x%29%5E2+=+15%5E2+%2B+%282x-3%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4x%5E2+=+225+%2B+4x%5E2+-12x+%2B+9 ALIGN=MIDDLE  ALT=\"4x%5E2+=+225+%2B+4x%5E2+-12x+%2B+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "225 -12x + 9 = 0<BR>\n" );
document.write( "12x = 234<BR>\n" );
document.write( "x = 19.5<BR>\n" );
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document.write( "The sides are 39, 36 & 15 </SPAN>\n" );
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