document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=442675>Question 442675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant wants to combine peanuts selling $2.40 per pound and cashews selling for $6.00 per pound to form 60 pounds which will sell at $3.00 per pound. What amount of each type of nut should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305414 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of pounds of cashews<BR>\n" );
document.write( "Then 60 - x = the number of pounds of peanuts<BR>\n" );
document.write( "We can write the following equation for the total dollar amount:<BR>\n" );
document.write( "2.4x + 6(60-x) = 3(60)<BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "2.4x + 360 - 6x = 180<BR>\n" );
document.write( "-3.6x = -180<BR>\n" );
document.write( "x = 50<BR>\n" );
document.write( "Therefore there are 60 - 50 = 10 pounds of peanuts<BR>\n" );
document.write( "Ans: 10 lbs. peanuts, 50 lbs. cashews </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );