document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=442532>Question 442532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Having serious trouble finding the answer. Would you please show me step by step so I can understand how the solution is found. 1/12y +3=11 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305248 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/12)y + 3 = 11<BR>\n" );
document.write( "Subtract 3 on both sides.<BR>\n" );
document.write( "(1/12)y + 3 -3 = 11 -3<BR>\n" );
document.write( "Simplify<BR>\n" );
document.write( "(1/12)y = 8<BR>\n" );
document.write( "We want y to have a coefficient of 1 so we need to multiply by 12 on both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cross%2812%29%281%2Fcross%2812%29%29y+=+8%2812%29 ALIGN=MIDDLE  ALT=\"cross%2812%29%281%2Fcross%2812%29%29y+=+8%2812%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Simplify<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+96 ALIGN=MIDDLE  ALT=\"y+=+96\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );