document.write( "Question 442530: The length of a rectangle is two times its width. the diagonal of of the rectangle is 10. Find the width of the rectangle \n" ); document.write( "

Algebra.Com's Answer #305245 by swincher4391(1107) $\"\"$ $\"About$

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The diagonal cuts the rectangle into two right triangles. Thus we can use the pythagorean theorem where our sides are the legs and the diagonal is the hypotenuse.\r
\n" ); document.write( "\n" ); document.write( "Let l be the length and let w be the width.\r
\n" ); document.write( "\n" ); document.write( "l^2 + w^2 = 10^2\r
\n" ); document.write( "\n" ); document.write( "Since the length is 2w, then we can can substitute l = 2w\r
\n" ); document.write( "\n" ); document.write( " $\"%282w%29%5E2+%2B+w%5E2+=+100\"$
\n" ); document.write( " $\"+4w%5E2+%2B+w%5E2+=+100%7D%0D%0A%7B%7B%7B+5w%5E2+=+100++=++w%5E2+=+20\"$ \r
\n" ); document.write( "\n" ); document.write( "So our width is $\"sqrt%2820%29\"$ or $\"2sqrt%285%29\"$ .\r
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