document.write( "Question 442473: In a right triangle c=6 feet 3 inches and tan B=1.2. How do you solve the triangle? \n" ); document.write( "
Algebra.Com's Answer #305190 by swincher4391(1107)\"\" \"About 
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It may be best to convert 6ft 3in into 6.25 inches.\r
\n" ); document.write( "\n" ); document.write( "Since tan(B) = b/a = 1.2, then b = 1.2a\r
\n" ); document.write( "\n" ); document.write( "a^2 + b^2 = (6.25)^2\r
\n" ); document.write( "\n" ); document.write( "a^2 + (1.2)^2a^2 = (6.25)^2
\n" ); document.write( "a^2 + 1.44a^2 = 39.0625\r
\n" ); document.write( "\n" ); document.write( "2.44a^2 = 39.0625
\n" ); document.write( "a^2 = 16.0092213
\n" ); document.write( "a = 4.000125.\r
\n" ); document.write( "\n" ); document.write( "We'll say a = 4.\r
\n" ); document.write( "\n" ); document.write( "4^2 + b^2 = (6.25^2)\r
\n" ); document.write( "\n" ); document.write( "b^2 = 39.0625 - 16 \r
\n" ); document.write( "\n" ); document.write( "b^2 = 23.0625\r
\n" ); document.write( "\n" ); document.write( "b = 4.80 = 4 ft 9.6 in\r
\n" ); document.write( "\n" ); document.write( "Or roughly 4 ft 10 in.\r
\n" ); document.write( "\n" ); document.write( "So we have \"a+=+4\", \"b+=+4.8\", \"c+=+6.25\"\r
\n" ); document.write( "\n" ); document.write( "or a =4, b = 4 ft 10in, c = 6 ft 3 in\r
\n" ); document.write( "\n" ); document.write( "I assume we want to find the angles as well?\r
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\n" ); document.write( "\n" ); document.write( "so A = arcsin(4/6.25) = 39.81º = \"40%BA\"
\n" ); document.write( "similarly with B B = arcsin(4.8/6.25) = 50.19º = \"50%BA\"\r
\n" ); document.write( "\n" ); document.write( "obviously C is 90º since it is a right triangle.\r
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