document.write( "Question 442456: solving by substitution. x+y=4
\n" ); document.write( " x=y+1
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Algebra.Com's Answer #305165 by swincher4391(1107)\"\" \"About 
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They have already solved the 2nd one for x. So let's use that.\r
\n" ); document.write( "\n" ); document.write( "Since we know x=y+1, then we can substitute that for where we see x in the 1st.\r
\n" ); document.write( "\n" ); document.write( "x+y=4
\n" ); document.write( "(y+1) + y =4
\n" ); document.write( "2y + 1 = 4
\n" ); document.write( "2y = 3
\n" ); document.write( "y = 3/2
\n" ); document.write( "-------
\n" ); document.write( "Now we need to plug in 3/2 back into one of our original equations.\r
\n" ); document.write( "\n" ); document.write( "Let's use the 2nd.\r
\n" ); document.write( "\n" ); document.write( "x = (3/2) + 1
\n" ); document.write( "x = 3/2 + 2/2
\n" ); document.write( "x = 5/2\r
\n" ); document.write( "\n" ); document.write( "So our solution is (5/2, 3/2) or \"x=5%2F2\"\"y=3%2F2\"
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