document.write( "Question 442441: Factor completely 81s^2+64-144s \n" ); document.write( "
Algebra.Com's Answer #305161 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
Recognize in your problem 81s^2-144s+64 that 81 and 64 are perfect squares.
\n" ); document.write( "\"%289s%29%5E2+=+81s%5E2\" and \"%288%29%5E2+=+64\"\r
\n" ); document.write( "\n" ); document.write( "Also recognize that the middle term is negative, while the last term is positive. In order to achieve a negative sum and positive product, both constants have to be negative... for instance -3 * -3 = 9, and -3 + -3 = -6.\r
\n" ); document.write( "\n" ); document.write( "Given this information, we have all we need to solve this.\r
\n" ); document.write( "\n" ); document.write( "Remember 81s^2 = (9s)^2 , so our first term in our factor will be 9s.
\n" ); document.write( "Similarly with 64 = 8^2.\r
\n" ); document.write( "\n" ); document.write( "So our factorization will be \"%289s-8%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Let's FOIL to make sure.\r
\n" ); document.write( "\n" ); document.write( "\"%289s-8%29%5E2+=+%289s-8%29%289s-8%29+=+81s%5E2+-72s+-72s+%2B+64+=+81s%5E2+-144s+%2B164\"
\n" ); document.write( "Check.\r
\n" ); document.write( "\n" ); document.write( "Hope this helped!
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