document.write( "Question 442433: 1/ x-1 + 1/2 = 2/ x^2 -1\r
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document.write( "I am trying to help my daughter with this problem, but I can't get it to work out. Can you please show how to explain. Thank you. \n" );
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Algebra.Com's Answer #305152 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "For this one: 1/ x-1 + 1/2 = 2/ x^2 -1 I'm assuming the x-1 and the x^2-1 are in the denominator. If so we can do the following: \n" ); document.write( "Multiply by (x-1)(x+1) to get: \n" ); document.write( "(x+1)+ 1/2(x-1)(x+1) \n" ); document.write( "NOw let's multiply by 2 to get rid of the fraction: \n" ); document.write( "2(x+1)+(x-1)(x+1) = 4 \n" ); document.write( "Expand this out: \n" ); document.write( "x^2+2x+1=4 \n" ); document.write( "Now subtract 4 from both sides to get: \n" ); document.write( "x^2+2x-3=0 \n" ); document.write( "Now factor: \n" ); document.write( "(x-1)(x+3)=0 \n" ); document.write( "Solve for x \n" ); document.write( "x=1 \n" ); document.write( "x=-3 \n" ); document.write( "x=1 doesn't work but \n" ); document.write( "x=-3 works so there we go. \n" ); document.write( "Make sense? \n" ); document.write( "RJ \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |