document.write( "Question 442376: I have a equation to the 3rd degree 1x^3-7x^2+19x-13 and it needs to be in quadratic from so that I may solve it and I am not sure how to get it that form. \n" ); document.write( "
Algebra.Com's Answer #305126 by Edwin McCravy(20055)\"\" \"About 
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document.write( "x³ - 7x² + 19x - 13 \r\n" );
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document.write( "The only possible zeros are the factors of 13, which are ±1 and ±13.\r\n" );
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document.write( "So we use synthetic division to try the easiest one first, 1:\r\n" );
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document.write( "1 | 1 -7  19 -13\r\n" );
document.write( "  |    1  -6  13\r\n" );
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document.write( "    1 -6  13   0\r\n" );
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document.write( "We're in luck because that left a 0 remainder.\r\n" );
document.write( "So we have factored the polynomial as\r\n" );
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document.write( "(x - 1)(x² - 6x + 13)\r\n" );
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document.write( "It has zeros found by setting each of those factors = 0\r\n" );
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document.write( "The first one gives 1 as a zero.  The other two zeros\r\n" );
document.write( "are found by the quadratic formula.\r\n" );
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document.write( "They are 3±2i\r\n" );
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document.write( "Edwin

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