document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5864>Question 5864</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train traveling at 60 kph covers a given distance in 3 hours. By how many kilometers per hour must its rate be increased so that it will travel the distance in one-half hour less time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3051 by </B><A HREF=/tutors/aboutme.mpl?userid=Abbey><B>Abbey(339)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Abbey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the distance it covers is the rate*time or 60*3 = 180<BR>\n" );
document.write( "so we can use rate*time=distance to determine the rate:<BR>\n" );
document.write( "x*2.5hours=180<BR>\n" );
document.write( "2.5x=180<BR>\n" );
document.write( "x=72 kmh </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );