document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=442334>Question 442334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Passing through the point (3,7)and parallel to the line with equation 5x+3y =12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305081 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the slope of your line 5x + 3y =12, solve for y.\r<BR>\n" );
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document.write( "3y = 12 -5x  --->  y = 4 - 5/3x.\r<BR>\n" );
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document.write( "A line that would be parallel to this line has the same slope.\r<BR>\n" );
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document.write( "So we have a point and we have a slope. That means we need to use POINT-SLOPE form.\r<BR>\n" );
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document.write( "Recall m being a slope and point (x1,y1) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y-y1+=+m%28x-x1%29 ALIGN=MIDDLE  ALT=\"y-y1+=+m%28x-x1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Then  y-7 = 5/3(x-3)\r<BR>\n" );
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document.write( "y-7 = 5/3x -5\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%285%2F3%29x+%2B+2 ALIGN=MIDDLE  ALT=\"y+=+%285%2F3%29x+%2B+2\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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