document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=442274>Question 442274</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Extremely confused daughter tried to help and she is stumped  this is from an algebra practice test     word problem is:  \r<BR>\n" );
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document.write( "A merchant has coffee worth $10 a pound that she wants to mix with 40 pounds of coffee worth $80 a pound to get a mixture that can be sold at $30 a pound.  How many pounds of the $10 coffee should be use.  Can you explain and show how you came up with answer please.  Thank you for any help you can give us. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305077 by </B><A HREF=/tutors/aboutme.mpl?userid=shree840><B>shree840(260)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shree840><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=shree840><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let us use x pounds of coffee total cost 10x cost of 40 lbs at $80=3200\r<BR>\n" );
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document.write( "total pounds=40+x  total cost = 30(40+x)<BR>\n" );
document.write( "10x+3200=30(40+x)=1200+30x<BR>\n" );
document.write( "2000=30x-10x=20x<BR>\n" );
document.write( "100=x\r<BR>\n" );
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document.write( "so we mix 100lbs at $10 with 40lbs at $80<BR>\n" );
document.write( "total cost 3200+1000=4200<BR>\n" );
document.write( "total lbs =100+40=140<BR>\n" );
document.write( "cost =$30  Ans </SPAN>\n" );
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