document.write( "Question 370013: Hi,\r
\n" ); document.write( "\n" ); document.write( "Another tutor tried helping me with the problem below but I still don't understand how to work it out.. Can someone please provide step by step instructions?\r
\n" ); document.write( "\n" ); document.write( "4/3x+2=6\r
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\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #305061 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
So we are given (4/3)x + 2 = 6.
\n" ); document.write( "The first thing we'll do is subtract 2 from both sides.
\n" ); document.write( "That will leave us with \"%284%2F3%29x++=+4\"
\n" ); document.write( "Now the trick is we want the coefficient of x to be 1. Then we have solved for it, right? So we need to cancel out the 4/3 with its reciprocal, 3/4. \r
\n" ); document.write( "\n" ); document.write( "Then the 3s and the 4s will cancel out leaving us with just 1.\r
\n" ); document.write( "\n" ); document.write( "So let's do that:\r
\n" ); document.write( "\n" ); document.write( "(3/4)(4/3)x = 4 (3/4)\r
\n" ); document.write( "\n" ); document.write( "For 4(3/4) [on the right side of the equation], the 4s cancel out and that leaves us with just 3.\r
\n" ); document.write( "\n" ); document.write( "So \"x+=+3\"\r
\n" ); document.write( "\n" ); document.write( "Please let me know if it still does not make sense.\r
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