document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5866>Question 5866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car starts at 7 AM and travels at 80 kph. Another car starts at 10 AM from the same place and goes in the same direction. How fast will it have to go to catch up with the first one by 4 PM of the same day? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3050 by </B><A HREF=/tutors/aboutme.mpl?userid=Abbey><B>Abbey(339)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Abbey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 80 = car 1 rate<BR>\n" );
document.write( "x=car 2 rate<BR>\n" );
document.write( "the distance when car 2 overtakes car 1 will be equal<BR>\n" );
document.write( "the time for car one is 9 hours<BR>\n" );
document.write( "the time for car two is 6 hours<BR>\n" );
document.write( "rate*time=d<BR>\n" );
document.write( "because the distance for both is the same we have two equations we can set equal to one another:<BR>\n" );
document.write( "80(9)=x(6)<BR>\n" );
document.write( "720=6x<BR>\n" );
document.write( "120=x<BR>\n" );
document.write( "car two must travel 120 kmh<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );