document.write( "Question 45883: 3x^2+13x=10
\n" ); document.write( "3x^2+13x-10=0\r
\n" ); document.write( "\n" ); document.write( "9+1+13x-10=0
\n" ); document.write( "13x=0
\n" ); document.write( "x=-13\r
\n" ); document.write( "\n" ); document.write( "Could you please help me? Am I even close? \r
\n" ); document.write( "\n" ); document.write( "Thank you, Michelle
\n" ); document.write( "

Algebra.Com's Answer #30495 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "\"3x%5E2%2B13x+=+10\" Subtract 10 from both sides of the equation.
\n" ); document.write( "\"3x%5E2%2B13x-10+=+0\" Factor the equation.
\n" ); document.write( "\"%283x-2%29%28x%2B5%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"3x-2+=+0\" and/or \"x%2B5+=+0\"
\n" ); document.write( "If \"3x-2+=+0\" then \"3x+=+2\" and \"x+=+2%2F3\"
\n" ); document.write( "If \"x%2B5+=+0\" then \"x+=+-5\"\r
\n" ); document.write( "\n" ); document.write( "The roots are:
\n" ); document.write( "\"x+=+2%2F3\"
\n" ); document.write( "\"x+=+-5\"
\n" ); document.write( "
\n" );