document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=442056>Question 442056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bobby and Joan found four consecutive integers such that 5 times the sum ofbthe second and third was 6 less than 7 times the first. What were their integers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #304942 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=304942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's represent the 4 integers as: x  (x+1) (x+2) (x+3) Now we can set up the following equation:<BR>\n" );
document.write( "5(x+1+x+2)=7(x)-6<BR>\n" );
document.write( "Rewritten as:<BR>\n" );
document.write( "10x+15=7x-6<BR>\n" );
document.write( "Subtract 7x and 15 from both sides to get:<BR>\n" );
document.write( "3x=-21<BR>\n" );
document.write( "Divide by 3:<BR>\n" );
document.write( "x=-7<BR>\n" );
document.write( "So now we know the integers are:<BR>\n" );
document.write( "-7, -6,-5,-4<BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );