document.write( "Question 45883: 3x^2+13x=10
\n" ); document.write( "3x^2+13x-10=0\r
\n" ); document.write( "\n" ); document.write( "9+1+13x-10=0
\n" ); document.write( "13x=0
\n" ); document.write( "x=-13\r
\n" ); document.write( "\n" ); document.write( "Could you please help me? Am I even close? \r
\n" ); document.write( "\n" ); document.write( "Thank you, Michelle \n" ); document.write( "

Algebra.Com's Answer #30493 by Nate(3500) $\"\"$ $\"About$

You can put this solution on YOUR website!
I have no idea what you are trying to do to solve this. It seems like you fill in random numbers. How does 13x = 0 turn into x = -13? Here:
\n" ); document.write( "3x^2 + 13x = 10
\n" ); document.write( "3x^2 + 13x - 10 = 0 find the sum of two factors of the product of (3) and (-10) that sum to (13) ~~~> they are 15 and -2
\n" ); document.write( "3x^2 + 15x - 2x - 10 = 0
\n" ); document.write( "(3x^2 + 15x) + (-2x - 10) = 0
\n" ); document.write( "3x(x + 5) - 2(x + 5) = 0
\n" ); document.write( "(3x - 2)(x + 5) = 0
\n" ); document.write( "3x - 2 = 0
\n" ); document.write( "3x = 2
\n" ); document.write( "x = 2/3
\n" ); document.write( "and
\n" ); document.write( "x + 5 = 0
\n" ); document.write( "x = -5
\n" ); document.write( " $\"graph%28600%2C600%2C-10%2C10%2C-10%2C10%2C3x%5E2+%2B+13x+-10%29\"$ \n" ); document.write( "

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