document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5867>Question 5867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mark leaves the house for school walking at the rate of 4 kph. Two hours later Joyce follows Mark at 4.5 kph. How long will it take Joyce to overtake Mark? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3049 by </B><A HREF=/tutors/aboutme.mpl?userid=Abbey><B>Abbey(339)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Abbey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mark's rate is 4 kph<BR>\n" );
document.write( "Mark's time time is t+2<BR>\n" );
document.write( "Joyce's rate is 4.5kph<BR>\n" );
document.write( "Joyce's time is t<BR>\n" );
document.write( "when Joyce overtakes Mark, they will be at the same distance, so we can use the formula rate * time = distance and set their distance = to one another:<BR>\n" );
document.write( "4(t+2)=4.5t<BR>\n" );
document.write( "4t+8=4.5t<BR>\n" );
document.write( "8=.5t<BR>\n" );
document.write( "16=t\r<BR>\n" );
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document.write( "this makes sense because in 16 hours time, Joyce will has walked 4.5*16 = 72km<BR>\n" );
document.write( "and in 18 hours time (he started two hours before her) Mark has walked 4*18=72km </SPAN>\n" );
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