document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=441941>Question 441941</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here i my word problem......please help!\r<BR>\n" );
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document.write( "the amout of radioactive substance present, in grams, at time t i months is gven by the formula y=6000(2)^-0.3t.  Find the numer of grams present in 3 years. If necessary, round to 3 decimal places. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #304893 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=304893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the amount of radioactive substance present, in grams, at time t months is gven by the formula y=6000(2)^-0.3t. Find the number of grams present in 3 years. If necessary, round to 3 decimal places.<BR>\n" );
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document.write( "y=6000(2)^-0.3t<BR>\n" );
document.write( "f(36) = 6000*2^(-0.3*36)<BR>\n" );
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document.write( "f(36) = 6000*2^(-10.8) = <BR>\n" );
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document.write( "f(36) = 3.3653 grams<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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