document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=441910>Question 441910</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given the amount (oz) of juice in 10 randomly selected juice bottles are:<BR>\n" );
document.write( "15.1, 15.6, 15.6, 15.9, 15.2, 15.9, 15.2,15.1, 15.8, 15.2.\r<BR>\n" );
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document.write( "construct a 94% confidence interval for the mean amount of the juice, u(with a wierd line), in the population of all such bottles. assume that the population has a normal distribution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #304890 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=304890\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a sample of 60 mice, a biologist found that 46% were able to run a maze in 30 seconds or less. Find the 90% limit for the population proportion of mice who can run that maze in 30 seconds or less?<BR>\n" );
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document.write( "p-hat = 0.46<BR>\n" );
document.write( "ME = 1.645*sqrt[0.46*0.54/60] = 0.1058<BR>\n" );
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document.write( "90% CI: 0.46-0.1058 < p < 0.46+0.1058<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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