document.write( "Question 441794: The perimeter of a rectangle is 78cm. If the length is six more than twice the width, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #304870 by AHBK(13)\"\" \"About 
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let W=width and L=length of rectangle
\n" ); document.write( "perimeter=78
\n" ); document.write( "2W+2L=78
\n" ); document.write( "and we have the length is six more twice the width so:
\n" ); document.write( "L=2w+6
\n" ); document.write( "subtitute 2W+6 instead of L above
\n" ); document.write( "so we have
\n" ); document.write( "2W+2(2W+6)=78
\n" ); document.write( "2W+4W+12=78
\n" ); document.write( "6W=78-12
\n" ); document.write( "6W=66
\n" ); document.write( "W=66/6
\n" ); document.write( "W=11cm
\n" ); document.write( "now substitute W=11cm in 2W+2L=78
\n" ); document.write( "so
\n" ); document.write( "2(11)+2L=78
\n" ); document.write( "22+2L=78
\n" ); document.write( "2L=78-22
\n" ); document.write( "2L=56
\n" ); document.write( "L=56/2
\n" ); document.write( "L=28cm
\n" ); document.write( "your welcome
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