document.write( "Question 441786: the volume of a balikbayan box filled with canned goods is 10648 dm3. if each can is 112 mL,how many cans are there in the box? \n" ); document.write( "
Algebra.Com's Answer #304868 by AHBK(13)\"\" \"About 
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the volume of the balikbayan is 10648 dm3 which is same as 10648Leters
\n" ); document.write( "1L=1000 ml
\n" ); document.write( "10648=X
\n" ); document.write( "using simple third rule u get:\r
\n" ); document.write( "\n" ); document.write( "X=(10648*1000)/1
\n" ); document.write( "so X= 10648000 ml
\n" ); document.write( "so volume of balikbayan is 10648000 ml
\n" ); document.write( "if each can is 112ml
\n" ); document.write( "and volume of balikbayan is 10648000 ml
\n" ); document.write( "then number of cans in there is equal to (10648000)/(112)
\n" ); document.write( "so (10648000)/(112)= 95071.42 cans in there
\n" ); document.write( "you can also do it by changing 112ml to leters n then dividing 10648 by the number you get
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