document.write( "Question 441789: Martin needs to mix some 40% alcohol solution with some 90% alcohol solution to obtain 15 liters of an 80% solution. How much of the 40% solution and how much of the 90% solution should he use?\r
\n" ); document.write( "\n" ); document.write( "I need the answer quickly, so it would be greatly appreciated if I could receive an answer within a few hours. Thank you very much.
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Algebra.Com's Answer #304822 by mananth(16946)\"\" \"About 
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percent ----------------quantity
\n" ); document.write( "Alcohol 40 ----------------x
\n" ); document.write( "Alcohol 90 ----------------15-x
\n" ); document.write( "Total 80.00% ----------------15
\n" ); document.write( "40x+90(15-x)=80 *15
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\n" ); document.write( "40x+1350-90x=1200
\n" ); document.write( "40x-90x =1200-1350
\n" ); document.write( "-50x=-150
\n" ); document.write( "/-50
\n" ); document.write( "x=3 liters 40.00%
\n" ); document.write( "12 liters 90.00%
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