document.write( "Question 441712: bob is twice as old as sue. ten years ago bob was three times as old as sue was then. find the present ages of sue and bob. \n" ); document.write( "
Algebra.Com's Answer #304805 by robertb(5830)![]() ![]() You can put this solution on YOUR website! bob = 2s \n" ); document.write( "sue = s\r \n" ); document.write( "\n" ); document.write( "2s - 10 = 3(s-10) \n" ); document.write( "==> 2s - 10 = 3s - 30 \n" ); document.write( "==> -10+ 30 = 3s - 2s\r \n" ); document.write( "\n" ); document.write( "==> s = 20, the age of sue now ==> bob is 40 years old now. \n" ); document.write( " |