document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=441645>Question 441645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use Descarte's rule of signs to determine the number of possible positive, negative, and nonreal complex solutions of the equation. Please help me.<BR>\n" );
document.write( "        • 4x^3-6x^2+x-3=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #304795 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=304795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 3 variations in signs ==> there could be 3 positive real roots, or just 1 positive real root.\r<BR>\n" );
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document.write( "Now when x is replaced by -x, the equation becomes <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-4x%5E3+-+6x%5E2+-+x+-+3+=+0 ALIGN=MIDDLE  ALT=\"-4x%5E3+-+6x%5E2+-+x+-+3+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, no variation in signs, hence there are no negative real roots.\r<BR>\n" );
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document.write( "Hence, either there 3 positive real roots, \r<BR>\n" );
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document.write( "OR\r<BR>\n" );
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document.write( "1 positive real root and 2 distinct complex roots. </SPAN>\n" );
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