document.write( "Question 441668: y varies directly with the sqquare of x and inversely with z. If y=16 when x=2 and z=3, find k, the constant of proportionality, and find y when x=5 and z=4 \n" ); document.write( "
Algebra.Com's Answer #304781 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"y+=+%28kx%5E2%29%2Fz\"\r
\n" ); document.write( "\n" ); document.write( "==> \"16+=+%28k2%5E2%29%2F3\" ==> 16 = 4k/3 ==> k = 12\r
\n" ); document.write( "\n" ); document.write( "==> \"y+=+%2812x%5E2%29%2Fz\"
\n" ); document.write( "==> \"y+=+%2812%2A25%29%2F4+=+3%2A25+=+75\"
\n" ); document.write( "
\n" );