document.write( "Question 441483: Solve
\n" ); document.write( "Log(x+2)=-log(x-1)+1
\n" ); document.write( "x+2=x-1+1
\n" ); document.write( "x-2=x \n" ); document.write( "

Algebra.Com's Answer #304722 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
Log(x+2)=-log(x-1)+1
\n" ); document.write( "Log(x+2)+log(x-1) = 1
\n" ); document.write( "Log(x+2)(x-1) = 1
\n" ); document.write( "(x+2)(x-1) = 10^1
\n" ); document.write( "x^2+x-2 = 10
\n" ); document.write( "x^2+x-12 = 0
\n" ); document.write( "(x+4)(x-3) = 0
\n" ); document.write( "x = {-4,3}
\n" ); document.write( "You can toss out the -4 (extraneous solution) leaving:
\n" ); document.write( "x = 3 \n" ); document.write( "

\n" );