document.write( "Question 441348: I have no idea how to do this my teacher never taught this type to us. I tried to look in the book but am just so confused with story problems and how to even go about doing this problem.\r
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document.write( "The amount remaining of a certain radioactive substance after t days is
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document.write( "A(t)=A e^(-0.0025t) where A is the begining amount. How much do we need to
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document.write( "begin with if we want 80 grams after 10 days? \n" );
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Algebra.Com's Answer #304651 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The amount remaining of a certain radioactive substance after t days is \n" ); document.write( "A(t) = A*e^(-0.0025t) where A is the beginning amount. \n" ); document.write( "How much do we need to begin with if we want 80 grams after 10 days? \n" ); document.write( ": \n" ); document.write( "write the equation: \n" ); document.write( " A*e^(-0.0025t) = A(t) \n" ); document.write( "Given values: \n" ); document.write( "A(t) = 80 \n" ); document.write( "t = 10 \n" ); document.write( "Replace A(t) and t and we have: \n" ); document.write( " A*e^(-0.0025*10) = 80 \n" ); document.write( ": \n" ); document.write( "A*e^(-0.025) = 80 \n" ); document.write( "Find e^-.025 on a calc, then we have: \n" ); document.write( ".97531A = 80 \n" ); document.write( "A = \n" ); document.write( "A = 82.025 grams will decay to 80 grams in 10 days \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check this on a calc: enter: 82.025*e^(-.0025*10): results: 79.9998 ~ 80 \n" ); document.write( ": \n" ); document.write( "How about this? Did we shed some light on this stuff for you?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |