document.write( "Question 441348: I have no idea how to do this my teacher never taught this type to us. I tried to look in the book but am just so confused with story problems and how to even go about doing this problem.\r
\n" ); document.write( "\n" ); document.write( "The amount remaining of a certain radioactive substance after t days is
\n" ); document.write( "A(t)=A e^(-0.0025t) where A is the begining amount. How much do we need to
\n" ); document.write( " 0 0
\n" ); document.write( "begin with if we want 80 grams after 10 days?
\n" ); document.write( "

Algebra.Com's Answer #304651 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The amount remaining of a certain radioactive substance after t days is
\n" ); document.write( "A(t) = A*e^(-0.0025t) where A is the beginning amount.
\n" ); document.write( "How much do we need to begin with if we want 80 grams after 10 days?
\n" ); document.write( ":
\n" ); document.write( "write the equation:
\n" ); document.write( " A*e^(-0.0025t) = A(t)
\n" ); document.write( "Given values:
\n" ); document.write( "A(t) = 80
\n" ); document.write( "t = 10
\n" ); document.write( "Replace A(t) and t and we have:
\n" ); document.write( " A*e^(-0.0025*10) = 80
\n" ); document.write( ":
\n" ); document.write( "A*e^(-0.025) = 80
\n" ); document.write( "Find e^-.025 on a calc, then we have:
\n" ); document.write( ".97531A = 80
\n" ); document.write( "A = \"80%2F.97531\"
\n" ); document.write( "A = 82.025 grams will decay to 80 grams in 10 days
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check this on a calc: enter: 82.025*e^(-.0025*10): results: 79.9998 ~ 80
\n" ); document.write( ":
\n" ); document.write( "How about this? Did we shed some light on this stuff for you?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );