document.write( "Question 441178: Find the number whoes product is 150 such that the one of the number is one more then four times the other number \n" ); document.write( "

Algebra.Com's Answer #304550 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x=one number
\n" ); document.write( "Then 4x+1=the other number
\n" ); document.write( "And we are told that:
\n" ); document.write( "x(4x+1)=150
\n" ); document.write( "4x^2+x=150 subtract 150 from each side
\n" ); document.write( "4x^2+x-150=0 quadratic in standard form
\n" ); document.write( "If we solve using the quadratic formula, we get:
\n" ); document.write( "x=(-1+-49)/8 or
\n" ); document.write( "x=-50/8=-25/4
\n" ); document.write( "and
\n" ); document.write( "x=48/8=6\r
\n" ); document.write( "\n" ); document.write( "Two solutions
\n" ); document.write( "CK
\n" ); document.write( "x=-25/4
\n" ); document.write( "4x+1=4(-25/4)+1=-24
\n" ); document.write( "(-25/4)(-24)=-25*-6=150
\n" ); document.write( "150=150
\n" ); document.write( "x=6
\n" ); document.write( "4x+1=25
\n" ); document.write( "6*25=150
\n" ); document.write( "150=150
\n" ); document.write( "Hope this helps--ptaylor \n" ); document.write( "

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