document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=441204>Question 441204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation 2x3 + x2 - 13x + 6=0.<BR>\n" );
document.write( "One of the roots lies between 1 and 3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #304539 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=304539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the equation 2x3 + x2 - 13x + 6=0.<BR>\n" );
document.write( "One of the roots lies between 1 and 3.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "If you are not allowed to use the graphing calculator, the best thing to do is try x=2 as one of the roots. Divide x-2 into the function, 2x3 + x2 - 13x + 6, by long division or synthetic division (sorry, this format does not allow me to show you how to do synthetic division, but perhaps you already know how.) You will then get a quotient,  2x^2+5x-3. You now have:<BR>\n" );
document.write( "(x-2)(2x^2+5x-3)=0<BR>\n" );
document.write( "(x-2)(2x+6)(x-1/2)=0<BR>\n" );
document.write( "ans: function has three real roots:<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "x=1/2<BR>\n" );
document.write( "x=-3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );