document.write( "Question 5081: Help--how do i figure this one out? Driving me crazy !!!\r
\n" ); document.write( "\n" ); document.write( "Twenty bearded men gather. Ten have eight-inch beards, six have ten-inch beards, and four have twelve-inch beards. What is the expected length of a randomly selected man from this group?\r
\n" ); document.write( "\n" ); document.write( "Tried 10/20 x 6/20 x 4/20 =12inches, that doesn't seem right. Please help!
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Algebra.Com's Answer #304534 by JWG(21)\"\" \"About 
You can put this solution on YOUR website!
They want to know who is the most likely to be picked. \r
\n" ); document.write( "\n" ); document.write( "8 inch: 10
\n" ); document.write( "10 inch: 6
\n" ); document.write( "12 inch: 4\r
\n" ); document.write( "\n" ); document.write( "There are 10+6+4=20 bearded men in the group. Immediately one can see that 8-inch bearded men make up most of the group. 10/20 = .5 or 50%. \r
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