document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=440890>Question 440890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can this be factored or is the problem wrong?<BR>\n" );
document.write( "x^3+8x^2-11x-12\r<BR>\n" );
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document.write( "I have tried all possible factors for 12 eg...1,2,3,4,6 and 12 both negative and positive values. When I substitute back in the eqn to find the first factor I do not get any zeros, hence not able to find the first factor before I start dividing. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #304459 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=304459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> not sure about wrong...but the graph shows NO integer factors\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28400%2C+400%2C+-12%2C+4%2C+-100%2C+150%2C+x%5E3%2B8x%5E2-11x-12%29 ALIGN=MIDDLE  ALT=\"graph%28400%2C+400%2C+-12%2C+4%2C+-100%2C+150%2C+x%5E3%2B8x%5E2-11x-12%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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