document.write( "Question 45848: determine the standard equation for a parabola with vertex(2,1) and y intercept (0,3). \n" ); document.write( "
Algebra.Com's Answer #30434 by stanbon(75887)\"\" \"About 
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determine the standard equation for a parabola with vertex(2,1) and y intercept (0,3).
\n" ); document.write( "Assuming you want the equation of the parabola that opens up
\n" ); document.write( "you have the standard vertex form of 4p(y-k)=(x-h)^2
\n" ); document.write( "We know h and k and need to find p, as follws:
\n" ); document.write( "4p(y-1)=(x-2)^2
\n" ); document.write( "Since the parabola passes through (0,3) we have:
\n" ); document.write( "4p(3-1)=(0-2)^2
\n" ); document.write( "4p(2)=4
\n" ); document.write( "p=1/2
\n" ); document.write( "The equation you want is 2(y-1)=(x-2)^2
\n" ); document.write( "This is standard vertex form.
\n" ); document.write( "You may want another form but you can manipulate this
\n" ); document.write( "to get the form you want.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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