document.write( "Question 440651: Solve this:
\n" ); document.write( "x-3y=8,4x+y=6 by substitution\r
\n" ); document.write( "\n" ); document.write( "thank you
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Algebra.Com's Answer #304331 by mananth(16946)\"\" \"About 
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x-3y=8 .............1
\n" ); document.write( "y=6-4x ---------2
\n" ); document.write( "y=6-4x
\n" ); document.write( "Plug the value of y in (1)
\n" ); document.write( "x-3(6-4x)=8
\n" ); document.write( "x-18+12 x= 8
\n" ); document.write( "x+12x=8+18
\n" ); document.write( "13x=26
\n" ); document.write( "/13
\n" ); document.write( "x=2
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "x -3y=8
\n" ); document.write( "1*2-3y=8
\n" ); document.write( "2-3y=8
\n" ); document.write( "-3y=6
\n" ); document.write( "/-3
\n" ); document.write( "y=-2
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