document.write( "Question 440619: The perimeter of a rectangular sign is not to exceed 50ft. The length is to be twice the width. What widths will meet these conditions? I think it starts like this: l=2w≤50 \n" ); document.write( "
Algebra.Com's Answer #304319 by stanbon(75887)\"\" \"About 
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The perimeter of a rectangular sign is not to exceed 50ft. The length is to be twice the width. What widths will meet these conditions? I think it starts like this: l=2w≤50
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\n" ); document.write( "Let the width be \"w\".
\n" ); document.write( "Then the length is \"2w\"
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\n" ); document.write( "Perimeter = 2(length + width)
\n" ); document.write( "2(2w + w) <= 50
\n" ); document.write( "3w <= 25
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\n" ); document.write( "width <= 25/3 ft
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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