document.write( "Question 440619: The perimeter of a rectangular sign is not to exceed 50ft. The length is to be twice the width. What widths will meet these conditions? I think it starts like this: l=2w≤50 \n" ); document.write( "
Algebra.Com's Answer #304319 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The perimeter of a rectangular sign is not to exceed 50ft. The length is to be twice the width. What widths will meet these conditions? I think it starts like this: l=2w≤50 \n" ); document.write( "----- \n" ); document.write( "Let the width be \"w\". \n" ); document.write( "Then the length is \"2w\" \n" ); document.write( "---- \n" ); document.write( "Perimeter = 2(length + width) \n" ); document.write( "2(2w + w) <= 50 \n" ); document.write( "3w <= 25 \n" ); document.write( "--- \n" ); document.write( "width <= 25/3 ft \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |