document.write( "Question 440606: The directions say: Solve the equation. Check your solution.\r
\n" ); document.write( "\n" ); document.write( "\"2m%2F%28m%2B4%29+=++3%2F%28m-1%29\"\r
\n" ); document.write( "\n" ); document.write( " 1. so what i did was cross multiply which gave me: \"2m%28m-1%29=3%28m%2B4%29\"
\n" ); document.write( " 2. then i distributed the 2m and 3 giving me: \"2m%5E2-2m+=+3m%2B12\"
\n" ); document.write( " 3. then i made it into a quadratic equation: \"2m%5E2-5m-12=0\"
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\n" ); document.write( " *** From here on I am lost, I tried factoring but i couldnt find anything that multiplies to -12 and adds
\n" ); document.write( " to -5\r
\n" ); document.write( "\n" ); document.write( " *** In the back of the book they showed the problem worked out, and from
\n" ); document.write( " here they managed to factor it to \"%282m%2B3%29%28m-4%29+=+0\" ; I'm confused
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Algebra.Com's Answer #304318 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2m^2 - 5m -12 = 0
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\n" ); document.write( "2m^2 -8m+3m -12 = 0
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\n" ); document.write( "2m(m-4)+3(m-4) = 0
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\n" ); document.write( "(m-4)(2m+3) = 0
\n" ); document.write( "m = 4 or m = -3/2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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