document.write( "Question 440478: A rectangle with an area pf 80cm^2 has a width that is three more than one half its length. What is the width of the rectangle?\r
\n" ); document.write( "\n" ); document.write( "I know that W=L1/2+3 and then I just got lost not having either the width or length.\r
\n" ); document.write( "\n" ); document.write( "Thank you for your help!
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Algebra.Com's Answer #304307 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangle with an area pf 80cm^2 has a width that is three more than one half its length.
\n" ); document.write( " What is the width of the rectangle?
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\n" ); document.write( "The area equation
\n" ); document.write( "L*W = 80
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\n" ); document.write( "We know that: W = (.5L+3)
\n" ); document.write( "Use this to replace W in the area equation
\n" ); document.write( "L(.5L+3) = 80
\n" ); document.write( ".5L^2 + 3L = 80
\n" ); document.write( "Get rid of that decimal, multiply by 2. results:
\n" ); document.write( "L^2 + 6L = 160
\n" ); document.write( "A quadratic equation:
\n" ); document.write( "L^2 + 6L - 160 = 0
\n" ); document.write( "This will factor to:
\n" ); document.write( "(L+16)(L-10) = 0
\n" ); document.write( "Two solutions, but we only want the positive one
\n" ); document.write( "L = 10 cm
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\n" ); document.write( "Find W, from the statement,\"width that is three more than one half its length.\"
\n" ); document.write( "W = .5(10) + 3
\n" ); document.write( "W = 5 + 3
\n" ); document.write( "W = 8 cm is the width
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\n" ); document.write( "Confirm this by finding the area with these values: 10 * 8 = 80
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