document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=440592>Question 440592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider the experiment of drawing two cards without replacement from an ordinary deck of 52 playing cards....what are the ODDS in favor of drawing a spade and a heart?\r<BR>\n" );
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document.write( "This is what I have: P(Spade)=13/52, P(heart without replacement)=13/51 so then I multiply and get 169/2652 reduced to 13/204. Now that is the probability of getting a heart and a spade, how to I find the odds? The formula for finding odds in favor is P(A)/1-P(A), so would my problem be set up as <BR>\n" );
document.write( "(13/204) / 1-(13/204)? If thats how it is set up, how do I carry out the math? I am very confused, please help! The answer in the book is 13:91 but I can not figure out how they got there.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #304306 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=304306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The only error is that you computed the probability of drawing a spade then a heart. However, you could also draw a heart then a spade. Hence, we would double the probability to 26/204 = 13/102.\r<BR>\n" );
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document.write( "The odds of drawing a spade and heart in some order is therefore (13/102)/(1 - 13/102) = (13/102)/(91/102) = 13:91. </SPAN>\n" );
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