document.write( "Question 45833: 4-3i
\n" ); document.write( "1+2i \r
\n" ); document.write( "\n" ); document.write( "Clarification, 4-3i is over 1+2i \r
\n" ); document.write( "\n" ); document.write( "Thank you, Michelle Turner
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Algebra.Com's Answer #30427 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(4-3i)/(1+2i)\r
\n" ); document.write( "\n" ); document.write( "Multiply numerator and denominator by the
\n" ); document.write( "conjugate of the denominator which is 1-2i, to get:\r
\n" ); document.write( "\n" ); document.write( "[(4-3i)(1-2i)]/[(1+2i)(1-2i)]
\n" ); document.write( "=[4-8i-3i-6]/[1+4]
\n" ); document.write( "=[-2-11i]/5
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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