document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=440347>Question 440347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation where ax^2+bx+c=0 with solutions of 2/5 and -5. Could you please answer within the hour? Thank you. A calculus teacher thought this would be fun homework worth a test grade. Please help!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #304212 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=304212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just saying, this is nowhere near calculus level.\r<BR>\n" );
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document.write( "A fundamental rule of polynomials is that if r is a root of the polynomial, then x-r is a factor of the polynomial. The polynomial with roots 2/5 and -5 can be expressed as (x - 2/5)(x + 5) = x^2 + 5x - (2/5)x - 2 = x^2 - (23/5)x - 2. We may multiply this polynomial by some arbitrary non-zero constant C (preferably 5 to clear the fractional coefficient). </SPAN>\n" );
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