document.write( "Question 440305: find the center of the ellipse: \"36x%5E2%2B64y2-36x-96y-531=0\" \n" ); document.write( "
Algebra.Com's Answer #304191 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "\"36x%5E2-36x+%2B64y2-96y+=+531\"
\n" ); document.write( " 36(x-1/2)^2 + 64(y-(3/4))^2 = 531 + 9 + 36
\n" ); document.write( " 36(x-1/2)^2 + 64(y-(3/4))^2 = 576
\n" ); document.write( " \"%28x-1%2F2%29%5E2%2F16+%2B+%28y-%283%2F4%29%29%5E2%2F9+=+1+\" C(.5,.75)\r
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