document.write( "Question 440208: there are 3 boys and three girls at a party. in how many ways can they be seated in a row if they must sit alternating boys and girls? \n" ); document.write( "
Algebra.Com's Answer #304150 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
They can be seated
\n" ); document.write( "(1) b g b g b g
\n" ); document.write( "or
\n" ); document.write( "(2) g b g b g b
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\n" ); document.write( "In (1), there are 3 boys that can be 1st
\n" ); document.write( "That leaves 2 boys that can be 2nd,
\n" ); document.write( "1 boy that can be 3rd
\n" ); document.write( "There are \"+3%2A2%2A1+=+6+\" possibilities
\n" ); document.write( "The same is true for the girls, so there are
\n" ); document.write( "\"+6%2A6+=+36+\" ways the boys and girls can be seated
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\n" ); document.write( "(2) follows the same rules, so the total number of
\n" ); document.write( "seating arrangements is \"+36+%2B+36+=+72+\"
\n" ); document.write( "You probably should get a second opinion, too.
\n" ); document.write( "These things are tricky.\r
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