document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=440177>Question 440177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the coffee shoppe sells a coffee blend made from two coffees, one costing $5/lbs and the other costing $6/lbs. If the blended coffee sells for $5.60/lb find how much of each coffee is used to obtain the desired blend. Assume that the weight of the blended coffee is 100lbs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #304135 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=304135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the coffee shoppe sells a coffee blend made from two coffees, one costing $5/lbs and the other costing $6/lbs. If the blended coffee sells for $5.60/lb find how much of each coffee is used to obtain the desired blend. Assume that the weight of the blended coffee is 100lbs.<BR>\n" );
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document.write( "Let x = amount (lbs) of $5 coffee<BR>\n" );
document.write( "then<BR>\n" );
document.write( "100-x = amount (lbs) of $6 coffee<BR>\n" );
document.write( "then<BR>\n" );
document.write( "5x + 6(100-x) = 5.60(100)<BR>\n" );
document.write( "5x + 600-6x = 560<BR>\n" );
document.write( "600-x = 560<BR>\n" );
document.write( "-x = -40<BR>\n" );
document.write( "x = 40 lbs ($5 coffee)<BR>\n" );
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document.write( "$6 coffee:<BR>\n" );
document.write( "100-x = 100-40 = 60 lbs<BR>\n" );
document.write( " </SPAN>\n" );
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