document.write( "Question 440003: Good Time Movie Theaters has studied the spending habits of customers at their concession counters to find the data normally distributed with a mean of $13.40 and a standard deviation of $2.10. A theater manager wants to know the probability of a customer spending more than $17.50 at the concession stand. \n" ); document.write( "

Algebra.Com's Answer #304119 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi
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document.write( "*Note: 
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document.write( "   z = (17.50-13.40)/2.10 = 1.9524
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document.write( " P(z > 1.9524) = 1 -  NORMSDIST(1.9524)= 1 - .9746 = .0254
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