document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=439933>Question 439933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, how many terms of the sequence -19,-15,-11,... must be taken to give a sum of 98? Thanks :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #304018 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=304018\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many terms of the sequence -19,-15,-11,... must be taken to give a sum of 98? <BR>\n" );
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document.write( "a = -19<BR>\n" );
document.write( "d = 4<BR>\n" );
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document.write( "S(n) = (n/2)(a + L) where L is the nth term:<BR>\n" );
document.write( "L = a + (n-1)d<BR>\n" );
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document.write( "Solve:<BR>\n" );
document.write( "98 = (n/2)(-19 + -19 +(n-1)4)<BR>\n" );
document.write( "196 = n(-38+4n-4)<BR>\n" );
document.write( "196 = n(4n-42)<BR>\n" );
document.write( "98 =n(2n-21)<BR>\n" );
document.write( "2n^2-21n-98 = 0<BR>\n" );
document.write( "(n-14)(2n+7) = 0<BR>\n" );
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document.write( "Positive solution:<BR>\n" );
document.write( "n = 14<BR>\n" );
document.write( "Ans: 14 terms<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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