document.write( "Question 439923: the product of two consecutive positive integers is 41 more than their sum. Find the integers. \n" ); document.write( "

Algebra.Com's Answer #304012 by stanbon(75887) $\"\"$ $\"About$

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the product of two consecutive positive integers is 41 more than their sum. Find the integers.
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\n" ); document.write( "Equation:
\n" ); document.write( "x(x+1) = x+x+1+41
\n" ); document.write( "---
\n" ); document.write( "x^2+x = 2x+42
\n" ); document.write( "---
\n" ); document.write( "x^2-x-42 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "(x-7)(x+6) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 7
\n" ); document.write( "x+1 = 8
\n" ); document.write( "=============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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